Base | Representation |
---|---|
bin | 100110101011110100… |
… | …1111111110001110001 |
3 | 21221102122021112121112 |
4 | 1031113221333301301 |
5 | 2330114200134203 |
6 | 102055241403105 |
7 | 6000450616241 |
oct | 1152751776161 |
9 | 257378245545 |
10 | 83075005553 |
11 | 32260747291 |
12 | 14125799495 |
13 | 7aac21b327 |
14 | 4041307b21 |
15 | 226342b6d8 |
hex | 1357a7fc71 |
83075005553 has 2 divisors, whose sum is σ = 83075005554. Its totient is φ = 83075005552.
The previous prime is 83075005529. The next prime is 83075005579. The reversal of 83075005553 is 35550057038.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 52963038769 + 30111966784 = 230137^2 + 173528^2 .
It is a cyclic number.
It is not a de Polignac number, because 83075005553 - 28 = 83075005297 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 83075005553.
It is not a weakly prime, because it can be changed into another prime (83075005513) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 41537502776 + 41537502777.
It is an arithmetic number, because the mean of its divisors is an integer number (41537502777).
Almost surely, 283075005553 is an apocalyptic number.
It is an amenable number.
83075005553 is a deficient number, since it is larger than the sum of its proper divisors (1).
83075005553 is an equidigital number, since it uses as much as digits as its factorization.
83075005553 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 315000, while the sum is 41.
The spelling of 83075005553 in words is "eighty-three billion, seventy-five million, five thousand, five hundred fifty-three".
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