Base | Representation |
---|---|
bin | 10010111001011000000011… |
… | …010010011001010101111111 |
3 | 101220021000102120121110202011 |
4 | 102321120003102121111333 |
5 | 41343114003104103042 |
6 | 452431045415512051 |
7 | 23335221411105655 |
oct | 2271300322312577 |
9 | 356230376543664 |
10 | 83107672331647 |
11 | 24531847467277 |
12 | 93a29a7388627 |
13 | 374b03487a262 |
14 | 167460b87cdd5 |
15 | 991c4bc3aa17 |
hex | 4b960349957f |
83107672331647 has 2 divisors, whose sum is σ = 83107672331648. Its totient is φ = 83107672331646.
The previous prime is 83107672331591. The next prime is 83107672331711. The reversal of 83107672331647 is 74613327670138.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 83107672331647 - 211 = 83107672329599 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 83107672331591 and 83107672331600.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (83107672331347) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 41553836165823 + 41553836165824.
It is an arithmetic number, because the mean of its divisors is an integer number (41553836165824).
Almost surely, 283107672331647 is an apocalyptic number.
83107672331647 is a deficient number, since it is larger than the sum of its proper divisors (1).
83107672331647 is an equidigital number, since it uses as much as digits as its factorization.
83107672331647 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 21337344, while the sum is 58.
The spelling of 83107672331647 in words is "eighty-three trillion, one hundred seven billion, six hundred seventy-two million, three hundred thirty-one thousand, six hundred forty-seven".
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