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83124211109047 is a prime number
BaseRepresentation
bin10010111001100111011101…
…000100110100110010110111
3101220022121010012020102012021
4102321213131010310302313
541343401341020442142
6452442422503134011
723336345304306613
oct2271473504646267
9356277105212167
1083124211109047
1124538864144549
1293a6042144307
13374c76c144784
14167533a1bc343
159923b8ba9267
hex4b99dd134cb7

83124211109047 has 2 divisors, whose sum is σ = 83124211109048. Its totient is φ = 83124211109046.

The previous prime is 83124211109039. The next prime is 83124211109081. The reversal of 83124211109047 is 74090111242138.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 83124211109047 - 23 = 83124211109039 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 83124211108994 and 83124211109012.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (83124211109087) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 41562105554523 + 41562105554524.

It is an arithmetic number, because the mean of its divisors is an integer number (41562105554524).

Almost surely, 283124211109047 is an apocalyptic number.

83124211109047 is a deficient number, since it is larger than the sum of its proper divisors (1).

83124211109047 is an equidigital number, since it uses as much as digits as its factorization.

83124211109047 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 96768, while the sum is 43.

The spelling of 83124211109047 in words is "eighty-three trillion, one hundred twenty-four billion, two hundred eleven million, one hundred nine thousand, forty-seven".