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83124211113149 is a prime number
BaseRepresentation
bin10010111001100111011101…
…000100110101110010111101
3101220022121010012020121211012
4102321213131010311302331
541343401341021110044
6452442422503205005
723336345304324563
oct2271473504656275
9356277105217735
1083124211113149
1124538864147638
1293a6042146765
13374c76c1465bb
14167533a1bda33
159923b8baa59e
hex4b99dd135cbd

83124211113149 has 2 divisors, whose sum is σ = 83124211113150. Its totient is φ = 83124211113148.

The previous prime is 83124211113067. The next prime is 83124211113173. The reversal of 83124211113149 is 94131111242138.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 57604790807524 + 25519420305625 = 7589782^2 + 5051675^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-83124211113149 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (83124211113049) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 41562105556574 + 41562105556575.

It is an arithmetic number, because the mean of its divisors is an integer number (41562105556575).

Almost surely, 283124211113149 is an apocalyptic number.

It is an amenable number.

83124211113149 is a deficient number, since it is larger than the sum of its proper divisors (1).

83124211113149 is an equidigital number, since it uses as much as digits as its factorization.

83124211113149 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 41472, while the sum is 41.

The spelling of 83124211113149 in words is "eighty-three trillion, one hundred twenty-four billion, two hundred eleven million, one hundred thirteen thousand, one hundred forty-nine".