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83141333114149 is a prime number
BaseRepresentation
bin10010111001110111011001…
…101000000101110100100101
3101220101020022110022101122101
4102321313121220011310211
541344141422234123044
6452454333503132101
723340522512043052
oct2271673150056445
9356336273271571
1083141333114149
1124545050064392
1293a94202a4031
13375126a4b463b
1416760c217a029
15992a6be30cd4
hex4b9dd9a05d25

83141333114149 has 2 divisors, whose sum is σ = 83141333114150. Its totient is φ = 83141333114148.

The previous prime is 83141333114053. The next prime is 83141333114167. The reversal of 83141333114149 is 94141133314138.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 56420859549924 + 26720473564225 = 7511382^2 + 5169185^2 .

It is a cyclic number.

It is not a de Polignac number, because 83141333114149 - 217 = 83141332983077 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 83141333114099 and 83141333114108.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (83141333114849) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 41570666557074 + 41570666557075.

It is an arithmetic number, because the mean of its divisors is an integer number (41570666557075).

Almost surely, 283141333114149 is an apocalyptic number.

It is an amenable number.

83141333114149 is a deficient number, since it is larger than the sum of its proper divisors (1).

83141333114149 is an equidigital number, since it uses as much as digits as its factorization.

83141333114149 is an evil number, because the sum of its binary digits is even.

The product of its digits is 373248, while the sum is 46.

The spelling of 83141333114149 in words is "eighty-three trillion, one hundred forty-one billion, three hundred thirty-three million, one hundred fourteen thousand, one hundred forty-nine".