Base | Representation |
---|---|
bin | 100110101110101010… |
… | …0000110001100000101 |
3 | 21221200020220002122112 |
4 | 1031131110012030011 |
5 | 2330313000143231 |
6 | 102112512110405 |
7 | 6003012503012 |
oct | 1153524061405 |
9 | 257606802575 |
10 | 83169927941 |
11 | 322aa28a941 |
12 | 14151535405 |
13 | 7ac5aa4919 |
14 | 404db76709 |
15 | 226b92b92b |
hex | 135d506305 |
83169927941 has 2 divisors, whose sum is σ = 83169927942. Its totient is φ = 83169927940.
The previous prime is 83169927923. The next prime is 83169927947. The reversal of 83169927941 is 14972996138.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 78526050625 + 4643877316 = 280225^2 + 68146^2 .
It is a cyclic number.
It is not a de Polignac number, because 83169927941 - 214 = 83169911557 is a prime.
It is a super-2 number, since 2×831699279412 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (83169927947) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 41584963970 + 41584963971.
It is an arithmetic number, because the mean of its divisors is an integer number (41584963971).
Almost surely, 283169927941 is an apocalyptic number.
It is an amenable number.
83169927941 is a deficient number, since it is larger than the sum of its proper divisors (1).
83169927941 is an equidigital number, since it uses as much as digits as its factorization.
83169927941 is an evil number, because the sum of its binary digits is even.
The product of its digits is 5878656, while the sum is 59.
The spelling of 83169927941 in words is "eighty-three billion, one hundred sixty-nine million, nine hundred twenty-seven thousand, nine hundred forty-one".
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