8325004341343 has 4 divisors (see below), whose sum is σ = 8325013441320. Its totient is φ = 8324995241368.

The previous prime is 8325004341287. The next prime is 8325004341347. The reversal of 8325004341343 is 3431434005238.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.

It is a cyclic number.

It is not a de Polignac number, because 8325004341343 - 2⁹ = 8325004340831 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 8325004341296 and 8325004341305.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (8325004341347) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3002233 + ... + 5065906.

It is an arithmetic number, because the mean of its divisors is an integer number (2081253360330).

Almost surely, 2^{8325004341343} is an apocalyptic number.

8325004341343 is a deficient number, since it is larger than the sum of its proper divisors (9099977).

8325004341343 is a wasteful number, since it uses less digits than its factorization.

8325004341343 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 9099976.

The product of its (nonzero) digits is 414720, while the sum is 40.

The spelling of 8325004341343 in words is "eight trillion, three hundred twenty-five billion, four million, three hundred forty-one thousand, three hundred forty-three".