Search a number
-
+
833000149 is a prime number
BaseRepresentation
bin110001101001101…
…001001011010101
32011001102210101101
4301221221023111
53201222001044
6214354030101
726433245602
oct6151511325
92131383341
10833000149
11398230383
121b2b78331
131037685c7
147c8b96a9
154d1e4cd4
hex31a692d5

833000149 has 2 divisors, whose sum is σ = 833000150. Its totient is φ = 833000148.

The previous prime is 833000123. The next prime is 833000167. The reversal of 833000149 is 941000338.

833000149 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 606045924 + 226954225 = 24618^2 + 15065^2 .

It is a cyclic number.

It is not a de Polignac number, because 833000149 - 25 = 833000117 is a prime.

It is a Chen prime.

It is equal to p42754501 and since 833000149 and 42754501 have the same sum of digits, it is a Honaker prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (833000849) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 416500074 + 416500075.

It is an arithmetic number, because the mean of its divisors is an integer number (416500075).

Almost surely, 2833000149 is an apocalyptic number.

It is an amenable number.

833000149 is a deficient number, since it is larger than the sum of its proper divisors (1).

833000149 is an equidigital number, since it uses as much as digits as its factorization.

833000149 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2592, while the sum is 28.

The square root of 833000149 is about 28861.7419605955. The cubic root of 833000149 is about 940.9105967780.

The spelling of 833000149 in words is "eight hundred thirty-three million, one hundred forty-nine", and thus it is an aban number.