Base | Representation |
---|---|
bin | 100111000101010110… |
… | …0010001101000001101 |
3 | 22000122022102210210111 |
4 | 1032022230101220031 |
5 | 2333342344202343 |
6 | 102320225440021 |
7 | 6030615530356 |
oct | 1161254215015 |
9 | 260568383714 |
10 | 83931240973 |
11 | 3265aaa7668 |
12 | 143244a0011 |
13 | 7bb77307c8 |
14 | 40c2d10d2d |
15 | 22b36b0c9d |
hex | 138ab11a0d |
83931240973 has 2 divisors, whose sum is σ = 83931240974. Its totient is φ = 83931240972.
The previous prime is 83931240959. The next prime is 83931240977. The reversal of 83931240973 is 37904213938.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 83730367044 + 200873929 = 289362^2 + 14173^2 .
It is a cyclic number.
It is not a de Polignac number, because 83931240973 - 29 = 83931240461 is a prime.
It is a super-2 number, since 2×839312409732 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (83931240977) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 41965620486 + 41965620487.
It is an arithmetic number, because the mean of its divisors is an integer number (41965620487).
Almost surely, 283931240973 is an apocalyptic number.
It is an amenable number.
83931240973 is a deficient number, since it is larger than the sum of its proper divisors (1).
83931240973 is an equidigital number, since it uses as much as digits as its factorization.
83931240973 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 979776, while the sum is 49.
The spelling of 83931240973 in words is "eighty-three billion, nine hundred thirty-one million, two hundred forty thousand, nine hundred seventy-three".
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