Base | Representation |
---|---|
bin | 100111000111001110… |
… | …1001001000101011001 |
3 | 22000210201020201221021 |
4 | 1032032131021011121 |
5 | 2334010030221211 |
6 | 102330403042441 |
7 | 6032313321106 |
oct | 1161635110531 |
9 | 260721221837 |
10 | 83994382681 |
11 | 326927039a0 |
12 | 14341670421 |
13 | 7bc783a771 |
14 | 40cb469aad |
15 | 22b8ed4771 |
hex | 138e749159 |
83994382681 has 4 divisors (see below), whose sum is σ = 91630235664. Its totient is φ = 76358529700.
The previous prime is 83994382657. The next prime is 83994382757. The reversal of 83994382681 is 18628349938.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 83994382681 - 27 = 83994382553 is a prime.
It is a super-2 number, since 2×839943826812 (a number of 23 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (83994382781) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3817926475 + ... + 3817926496.
It is an arithmetic number, because the mean of its divisors is an integer number (22907558916).
Almost surely, 283994382681 is an apocalyptic number.
It is an amenable number.
83994382681 is a deficient number, since it is larger than the sum of its proper divisors (7635852983).
83994382681 is a wasteful number, since it uses less digits than its factorization.
83994382681 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 7635852982.
The product of its digits is 17915904, while the sum is 61.
The spelling of 83994382681 in words is "eighty-three billion, nine hundred ninety-four million, three hundred eighty-two thousand, six hundred eighty-one".
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