Base | Representation |
---|---|
bin | 10011010010000000100001… |
… | …111101010010111110110011 |
3 | 102010020211122221220020112201 |
4 | 103102000201331102332303 |
5 | 42103332211411241013 |
6 | 500204433502204031 |
7 | 23601425031005113 |
oct | 2322004175227663 |
9 | 363224587806481 |
10 | 84800404008883 |
11 | 25024716359342 |
12 | 9616a77883617 |
13 | 384184a520514 |
14 | 16d250bb85043 |
15 | 9c0cbe3dc3dd |
hex | 4d2021f52fb3 |
84800404008883 has 2 divisors, whose sum is σ = 84800404008884. Its totient is φ = 84800404008882.
The previous prime is 84800404008839. The next prime is 84800404008907. The reversal of 84800404008883 is 38880040400848.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 84800404008883 - 229 = 84799867137971 is a prime.
It is a super-2 number, since 2×848004040088832 (a number of 29 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (84800404008833) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 42400202004441 + 42400202004442.
It is an arithmetic number, because the mean of its divisors is an integer number (42400202004442).
Almost surely, 284800404008883 is an apocalyptic number.
84800404008883 is a deficient number, since it is larger than the sum of its proper divisors (1).
84800404008883 is an equidigital number, since it uses as much as digits as its factorization.
84800404008883 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 6291456, while the sum is 55.
The spelling of 84800404008883 in words is "eighty-four trillion, eight hundred billion, four hundred four million, eight thousand, eight hundred eighty-three".
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