Base | Representation |
---|---|
bin | 100111101001001010… |
… | …0111100000111101101 |
3 | 22010202001220201021111 |
4 | 1033102110330013231 |
5 | 2343323032124432 |
6 | 103035401232021 |
7 | 6102451160335 |
oct | 1172224740755 |
9 | 263661821244 |
10 | 85133083117 |
11 | 33117451435 |
12 | 145baa92611 |
13 | 804971b5c4 |
14 | 41987a00c5 |
15 | 2333e62347 |
hex | 13d253c1ed |
85133083117 has 2 divisors, whose sum is σ = 85133083118. Its totient is φ = 85133083116.
The previous prime is 85133083067. The next prime is 85133083163. The reversal of 85133083117 is 71138033158.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 43103572996 + 42029510121 = 207614^2 + 205011^2 .
It is a cyclic number.
It is not a de Polignac number, because 85133083117 - 215 = 85133050349 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 85133083117.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (85133083417) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 42566541558 + 42566541559.
It is an arithmetic number, because the mean of its divisors is an integer number (42566541559).
Almost surely, 285133083117 is an apocalyptic number.
It is an amenable number.
85133083117 is a deficient number, since it is larger than the sum of its proper divisors (1).
85133083117 is an equidigital number, since it uses as much as digits as its factorization.
85133083117 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 60480, while the sum is 40.
The spelling of 85133083117 in words is "eighty-five billion, one hundred thirty-three million, eighty-three thousand, one hundred seventeen".
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