Base | Representation |
---|---|
bin | 100111101100110100… |
… | …0101010000011100101 |
3 | 22011001121121220202101 |
4 | 1033121220222003211 |
5 | 2344100424130032 |
6 | 103055501212101 |
7 | 6105500300212 |
oct | 1173150520345 |
9 | 264047556671 |
10 | 85255692517 |
11 | 3317a685716 |
12 | 14633b61031 |
13 | 8068c4a148 |
14 | 41aab98b09 |
15 | 233ead0de7 |
hex | 13d9a2a0e5 |
85255692517 has 2 divisors, whose sum is σ = 85255692518. Its totient is φ = 85255692516.
The previous prime is 85255692493. The next prime is 85255692551. The reversal of 85255692517 is 71529655258.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 62803367236 + 22452325281 = 250606^2 + 149841^2 .
It is a cyclic number.
It is not a de Polignac number, because 85255692517 - 211 = 85255690469 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (85255692017) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 42627846258 + 42627846259.
It is an arithmetic number, because the mean of its divisors is an integer number (42627846259).
Almost surely, 285255692517 is an apocalyptic number.
It is an amenable number.
85255692517 is a deficient number, since it is larger than the sum of its proper divisors (1).
85255692517 is an equidigital number, since it uses as much as digits as its factorization.
85255692517 is an evil number, because the sum of its binary digits is even.
The product of its digits is 7560000, while the sum is 55.
The spelling of 85255692517 in words is "eighty-five billion, two hundred fifty-five million, six hundred ninety-two thousand, five hundred seventeen".
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