Base | Representation |
---|---|
bin | 100111101111001011… |
… | …0001000001110111111 |
3 | 22011021010100000002200 |
4 | 1033132112020032333 |
5 | 2344231142041341 |
6 | 103111403122543 |
7 | 6110450110266 |
oct | 1173626101677 |
9 | 264233300080 |
10 | 85334721471 |
11 | 332102532aa |
12 | 14656513453 |
13 | 807c42a53c |
14 | 41b748b5dd |
15 | 23469e1db6 |
hex | 13de5883bf |
85334721471 has 6 divisors (see below), whose sum is σ = 123261264360. Its totient is φ = 56889814308.
The previous prime is 85334721379. The next prime is 85334721497. The reversal of 85334721471 is 17412743358.
85334721471 is a `hidden beast` number, since 8 + 5 + 33 + 472 + 147 + 1 = 666.
It is not a de Polignac number, because 85334721471 - 217 = 85334590399 is a prime.
It is a super-3 number, since 3×853347214713 (a number of 34 digits) contains 333 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (85334721971) by changing a digit.
It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 4740817851 + ... + 4740817868.
It is an arithmetic number, because the mean of its divisors is an integer number (20543544060).
Almost surely, 285334721471 is an apocalyptic number.
85334721471 is a deficient number, since it is larger than the sum of its proper divisors (37926542889).
85334721471 is a wasteful number, since it uses less digits than its factorization.
85334721471 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 9481635725 (or 9481635722 counting only the distinct ones).
The product of its digits is 564480, while the sum is 45.
The spelling of 85334721471 in words is "eighty-five billion, three hundred thirty-four million, seven hundred twenty-one thousand, four hundred seventy-one".
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