Base | Representation |
---|---|
bin | 100111101111001100… |
… | …0110111010100111011 |
3 | 22011021011200102212220 |
4 | 1033132120313110323 |
5 | 2344231333014101 |
6 | 103111430335123 |
7 | 6110456155221 |
oct | 1173630672473 |
9 | 264234612786 |
10 | 85335438651 |
11 | 332106a3111 |
12 | 146567ba4a3 |
13 | 807c61bac8 |
14 | 41b75d6b11 |
15 | 2346ad4636 |
hex | 13de63753b |
85335438651 has 4 divisors (see below), whose sum is σ = 113780584872. Its totient is φ = 56890292432.
The previous prime is 85335438623. The next prime is 85335438707. The reversal of 85335438651 is 15683453358.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 85335438651 - 27 = 85335438523 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 85335438594 and 85335438603.
It is not an unprimeable number, because it can be changed into a prime (85335438151) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 14222573106 + ... + 14222573111.
It is an arithmetic number, because the mean of its divisors is an integer number (28445146218).
Almost surely, 285335438651 is an apocalyptic number.
85335438651 is a deficient number, since it is larger than the sum of its proper divisors (28445146221).
85335438651 is a wasteful number, since it uses less digits than its factorization.
85335438651 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 28445146220.
The product of its digits is 5184000, while the sum is 51.
The spelling of 85335438651 in words is "eighty-five billion, three hundred thirty-five million, four hundred thirty-eight thousand, six hundred fifty-one".
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