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85417879011263 is a prime number
BaseRepresentation
bin10011011010111111100110…
…010101011111111110111111
3102012102212110212001101201022
4103122333212111133332333
542143441304011330023
6501400233142334355
723664144445636001
oct2332774625377677
9365385425041638
1085417879011263
1125242578953867
1296b6682a2a3bb
133887b436b3106
141714366c34371
159d1dad4ad7c8
hex4dafe655ffbf

85417879011263 has 2 divisors, whose sum is σ = 85417879011264. Its totient is φ = 85417879011262.

The previous prime is 85417879011247. The next prime is 85417879011341. The reversal of 85417879011263 is 36211097871458.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 85417879011263 - 24 = 85417879011247 is a prime.

It is a super-3 number, since 3×854178790112633 (a number of 43 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 85417879011196 and 85417879011205.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (85417879013263) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 42708939505631 + 42708939505632.

It is an arithmetic number, because the mean of its divisors is an integer number (42708939505632).

It is a 1-persistent number, because it is pandigital, but 2⋅85417879011263 = 170835758022526 is not.

Almost surely, 285417879011263 is an apocalyptic number.

85417879011263 is a deficient number, since it is larger than the sum of its proper divisors (1).

85417879011263 is an equidigital number, since it uses as much as digits as its factorization.

85417879011263 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 20321280, while the sum is 62.

The spelling of 85417879011263 in words is "eighty-five trillion, four hundred seventeen billion, eight hundred seventy-nine million, eleven thousand, two hundred sixty-three".