Base | Representation |
---|---|
bin | 10011011110000110010100… |
… | …100011010001011111011101 |
3 | 102020012021020102002200001121 |
4 | 103132012110203101133131 |
5 | 42210440302321130010 |
6 | 502042242224010541 |
7 | 24015440222040115 |
oct | 2336062443213735 |
9 | 366167212080047 |
10 | 85631255255005 |
11 | 25315014209959 |
12 | 972bab2160a51 |
13 | 38a1cba0184c5 |
14 | 1720809620045 |
15 | 9d76eae043da |
hex | 4de1948d17dd |
85631255255005 has 32 divisors (see below), whose sum is σ = 107042375059200. Its totient is φ = 65682158502912.
The previous prime is 85631255254999. The next prime is 85631255255017. The reversal of 85631255255005 is 50055255213658.
It is a cyclic number.
It is not a de Polignac number, because 85631255255005 - 25 = 85631255254973 is a prime.
It is a super-3 number, since 3×856312552550053 (a number of 43 digits) contains 333 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 22939909 + ... + 26410261.
It is an arithmetic number, because the mean of its divisors is an integer number (3345074220600).
Almost surely, 285631255255005 is an apocalyptic number.
It is an amenable number.
85631255255005 is a deficient number, since it is larger than the sum of its proper divisors (21411119804195).
85631255255005 is a wasteful number, since it uses less digits than its factorization.
85631255255005 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 3471573.
The product of its (nonzero) digits is 9000000, while the sum is 52.
The spelling of 85631255255005 in words is "eighty-five trillion, six hundred thirty-one billion, two hundred fifty-five million, two hundred fifty-five thousand, five".
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