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86011314024065 = 517202262804813
BaseRepresentation
bin10011100011101000010001…
…110100011010111010000001
3102021112121020100201112210112
4103203220101310122322001
542233202132342232230
6502533015134241105
724055053354213443
oct2343502164327201
9367477210645715
1086011314024065
1125451214502301
12979169b056195
1338cbaa81b77c1
141734d81238493
159e2541cded95
hex4e3a11d1ae81

86011314024065 has 4 divisors (see below), whose sum is σ = 103213576828884. Its totient is φ = 68809051219248.

The previous prime is 86011314024059. The next prime is 86011314024109. The reversal of 86011314024065 is 56042041311068.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 53236227171856 + 32775086852209 = 7296316^2 + 5724953^2 .

It is a cyclic number.

It is not a de Polignac number, because 86011314024065 - 232 = 86007019056769 is a prime.

It is a super-2 number, since 2×860113140240652 (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8601131402402 + ... + 8601131402411.

It is an arithmetic number, because the mean of its divisors is an integer number (25803394207221).

Almost surely, 286011314024065 is an apocalyptic number.

It is an amenable number.

86011314024065 is a deficient number, since it is larger than the sum of its proper divisors (17202262804819).

86011314024065 is a wasteful number, since it uses less digits than its factorization.

86011314024065 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 17202262804818.

The product of its (nonzero) digits is 138240, while the sum is 41.

The spelling of 86011314024065 in words is "eighty-six trillion, eleven billion, three hundred fourteen million, twenty-four thousand, sixty-five".

Divisors: 1 5 17202262804813 86011314024065