Base | Representation |
---|---|
bin | 10011100011101000010001… |
… | …110100011010111010000001 |
3 | 102021112121020100201112210112 |
4 | 103203220101310122322001 |
5 | 42233202132342232230 |
6 | 502533015134241105 |
7 | 24055053354213443 |
oct | 2343502164327201 |
9 | 367477210645715 |
10 | 86011314024065 |
11 | 25451214502301 |
12 | 979169b056195 |
13 | 38cbaa81b77c1 |
14 | 1734d81238493 |
15 | 9e2541cded95 |
hex | 4e3a11d1ae81 |
86011314024065 has 4 divisors (see below), whose sum is σ = 103213576828884. Its totient is φ = 68809051219248.
The previous prime is 86011314024059. The next prime is 86011314024109. The reversal of 86011314024065 is 56042041311068.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 53236227171856 + 32775086852209 = 7296316^2 + 5724953^2 .
It is a cyclic number.
It is not a de Polignac number, because 86011314024065 - 232 = 86007019056769 is a prime.
It is a super-2 number, since 2×860113140240652 (a number of 29 digits) contains 22 as substring.
It is a Duffinian number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8601131402402 + ... + 8601131402411.
It is an arithmetic number, because the mean of its divisors is an integer number (25803394207221).
Almost surely, 286011314024065 is an apocalyptic number.
It is an amenable number.
86011314024065 is a deficient number, since it is larger than the sum of its proper divisors (17202262804819).
86011314024065 is a wasteful number, since it uses less digits than its factorization.
86011314024065 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 17202262804818.
The product of its (nonzero) digits is 138240, while the sum is 41.
The spelling of 86011314024065 in words is "eighty-six trillion, eleven billion, three hundred fourteen million, twenty-four thousand, sixty-five".
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