Base | Representation |
---|---|
bin | 101001101110100101… |
… | …0010010000111011111 |
3 | 22120022001122210222221 |
4 | 1103131022102013133 |
5 | 2432010102300203 |
6 | 105055521050211 |
7 | 6321420533413 |
oct | 1233512220737 |
9 | 276261583887 |
10 | 89609806303 |
11 | 35004443866 |
12 | 1544a186967 |
13 | 85b1035334 |
14 | 44a116ad43 |
15 | 24e6ea3abd |
hex | 14dd2921df |
89609806303 has 4 divisors (see below), whose sum is σ = 92500445248. Its totient is φ = 86719167360.
The previous prime is 89609806301. The next prime is 89609806327. The reversal of 89609806303 is 30360890698.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 89609806303 - 21 = 89609806301 is a prime.
It is a super-2 number, since 2×896098063032 (a number of 23 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (89609806301) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1445319426 + ... + 1445319487.
It is an arithmetic number, because the mean of its divisors is an integer number (23125111312).
Almost surely, 289609806303 is an apocalyptic number.
89609806303 is a deficient number, since it is larger than the sum of its proper divisors (2890638945).
89609806303 is a wasteful number, since it uses less digits than its factorization.
89609806303 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2890638944.
The product of its (nonzero) digits is 1679616, while the sum is 52.
The spelling of 89609806303 in words is "eighty-nine billion, six hundred nine million, eight hundred six thousand, three hundred three".
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