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9000699573253 is a prime number
BaseRepresentation
bin1000001011111010001110…
…0000000011010000000101
31011212110101020011211102211
42002332203200003100011
52134431413042321003
631050510404503421
71616164504021363
oct202764340032005
934773336154384
109000699573253
1129601a2296943
1210144900aab71
135039baaaca6b
142318c998c633
151091ded1796d
hex82fa3803405

9000699573253 has 2 divisors, whose sum is σ = 9000699573254. Its totient is φ = 9000699573252.

The previous prime is 9000699573167. The next prime is 9000699573301. The reversal of 9000699573253 is 3523759960009.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 6869677694049 + 2131021879204 = 2621007^2 + 1459802^2 .

It is a cyclic number.

It is not a de Polignac number, because 9000699573253 - 213 = 9000699565061 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (9000699573653) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 4500349786626 + 4500349786627.

It is an arithmetic number, because the mean of its divisors is an integer number (4500349786627).

Almost surely, 29000699573253 is an apocalyptic number.

It is an amenable number.

9000699573253 is a deficient number, since it is larger than the sum of its proper divisors (1).

9000699573253 is an equidigital number, since it uses as much as digits as its factorization.

9000699573253 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 13778100, while the sum is 58.

The spelling of 9000699573253 in words is "nine trillion, six hundred ninety-nine million, five hundred seventy-three thousand, two hundred fifty-three".