Base | Representation |
---|---|
bin | 1000010001101100001011… |
… | …1111101101001111101111 |
3 | 1012012221201111102122222221 |
4 | 2010123002333231033233 |
5 | 2143043311111310411 |
6 | 31204253215220211 |
7 | 1626311533361662 |
oct | 204330277551757 |
9 | 35187644378887 |
10 | 9100012213231 |
11 | 2999325726205 |
12 | 102b787817667 |
13 | 5101870874a4 |
14 | 23662b6056d9 |
15 | 10baa3a2a071 |
hex | 846c2fed3ef |
9100012213231 has 2 divisors, whose sum is σ = 9100012213232. Its totient is φ = 9100012213230.
The previous prime is 9100012213177. The next prime is 9100012213247. The reversal of 9100012213231 is 1323122100019.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 9100012213231 - 215 = 9100012180463 is a prime.
It is a super-2 number, since 2×91000122132312 (a number of 27 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 9100012213196 and 9100012213205.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (9100012211231) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 4550006106615 + 4550006106616.
It is an arithmetic number, because the mean of its divisors is an integer number (4550006106616).
Almost surely, 29100012213231 is an apocalyptic number.
9100012213231 is a deficient number, since it is larger than the sum of its proper divisors (1).
9100012213231 is an equidigital number, since it uses as much as digits as its factorization.
9100012213231 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 648, while the sum is 25.
The spelling of 9100012213231 in words is "nine trillion, one hundred billion, twelve million, two hundred thirteen thousand, two hundred thirty-one".
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