913433 has 2 divisors, whose sum is σ = 913434. Its totient is φ = 913432.

The previous prime is 913421. The next prime is 913441. The reversal of 913433 is 334319.

913433 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 851929 + 61504 = 923^2 + 248^2 .

It is an emirp because it is prime and its reverse (334319) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 913433 - 2⁴ = 913417 is a prime.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 913399 and 913408.

It is an inconsummate number, since it does not exist a number n which divided by its sum of digits gives 913433.

It is not a weakly prime, because it can be changed into another prime (913483) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 456716 + 456717.

It is an arithmetic number, because the mean of its divisors is an integer number (456717).

2⁹¹³⁴³³ is an apocalyptic number.

It is an amenable number.

913433 is a deficient number, since it is larger than the sum of its proper divisors (1).

913433 is an equidigital number, since it uses as much as digits as its factorization.

913433 is an evil number, because the sum of its binary digits is even.

The product of its digits is 972, while the sum is 23.

The square root of 913433 is about 955.7368884793. The cubic root of 913433 is about 97.0269171057.

The spelling of 913433 in words is "nine hundred thirteen thousand, four hundred thirty-three".