Base | Representation |
---|---|
bin | 101010110100101101… |
… | …1100000111111111001 |
3 | 22210101001212020121222 |
4 | 1111221123200333321 |
5 | 3001320030241240 |
6 | 110125225041425 |
7 | 6433634512064 |
oct | 1255133407771 |
9 | 283331766558 |
10 | 91963133945 |
11 | 36001878741 |
12 | 159a6326275 |
13 | 889775c3b7 |
14 | 464591b8db |
15 | 25d38aaeb5 |
hex | 15696e0ff9 |
91963133945 has 4 divisors (see below), whose sum is σ = 110355760740. Its totient is φ = 73570507152.
The previous prime is 91963133891. The next prime is 91963133987. The reversal of 91963133945 is 54933136919.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 54933136919 = 77969 ⋅704551.
It can be written as a sum of positive squares in 2 ways, for example, as 73129139776 + 18833994169 = 270424^2 + 137237^2 .
It is a cyclic number.
It is not a de Polignac number, because 91963133945 - 212 = 91963129849 is a prime.
It is a super-3 number, since 3×919631339453 (a number of 34 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 9196313390 + ... + 9196313399.
It is an arithmetic number, because the mean of its divisors is an integer number (27588940185).
Almost surely, 291963133945 is an apocalyptic number.
It is an amenable number.
91963133945 is a deficient number, since it is larger than the sum of its proper divisors (18392626795).
91963133945 is a wasteful number, since it uses less digits than its factorization.
91963133945 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 18392626794.
The product of its digits is 2361960, while the sum is 53.
The spelling of 91963133945 in words is "ninety-one billion, nine hundred sixty-three million, one hundred thirty-three thousand, nine hundred forty-five".
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