Base | Representation |
---|---|
bin | 101010111010001110… |
… | …0101110011010010011 |
3 | 22210211221201102201211 |
4 | 1111310130232122103 |
5 | 3002204342003103 |
6 | 110155431240551 |
7 | 6441341036254 |
oct | 1256434563223 |
9 | 283757642654 |
10 | 92148000403 |
11 | 36097164638 |
12 | 15a38219157 |
13 | 88c6b48334 |
14 | 46622c0b2b |
15 | 25e4c2636d |
hex | 157472e693 |
92148000403 has 2 divisors, whose sum is σ = 92148000404. Its totient is φ = 92148000402.
The previous prime is 92148000349. The next prime is 92148000457. The reversal of 92148000403 is 30400084129.
It is a balanced prime because it is at equal distance from previous prime (92148000349) and next prime (92148000457).
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-92148000403 is a prime.
It is not a weakly prime, because it can be changed into another prime (92148001403) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 46074000201 + 46074000202.
It is an arithmetic number, because the mean of its divisors is an integer number (46074000202).
Almost surely, 292148000403 is an apocalyptic number.
92148000403 is a deficient number, since it is larger than the sum of its proper divisors (1).
92148000403 is an equidigital number, since it uses as much as digits as its factorization.
92148000403 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6912, while the sum is 31.
The spelling of 92148000403 in words is "ninety-two billion, one hundred forty-eight million, four hundred three", and thus it is an aban number.
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