Base | Representation |
---|---|
bin | 101011010111111010… |
… | …0010011101111000101 |
3 | 22220102100221101220211 |
4 | 1112233310103233011 |
5 | 3011224333211331 |
6 | 110442331555421 |
7 | 6505124156044 |
oct | 1265764235705 |
9 | 286370841824 |
10 | 93144038341 |
11 | 36558421692 |
12 | 160758bbb71 |
13 | 8a252c8cb3 |
14 | 47186ba55b |
15 | 26523c38b1 |
hex | 15afd13bc5 |
93144038341 has 2 divisors, whose sum is σ = 93144038342. Its totient is φ = 93144038340.
The previous prime is 93144038321. The next prime is 93144038401. The reversal of 93144038341 is 14383044139.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 48365246241 + 44778792100 = 219921^2 + 211610^2 .
It is a cyclic number.
It is not a de Polignac number, because 93144038341 - 27 = 93144038213 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 93144038294 and 93144038303.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (93144038321) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 46572019170 + 46572019171.
It is an arithmetic number, because the mean of its divisors is an integer number (46572019171).
Almost surely, 293144038341 is an apocalyptic number.
It is an amenable number.
93144038341 is a deficient number, since it is larger than the sum of its proper divisors (1).
93144038341 is an equidigital number, since it uses as much as digits as its factorization.
93144038341 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 124416, while the sum is 40.
The spelling of 93144038341 in words is "ninety-three billion, one hundred forty-four million, thirty-eight thousand, three hundred forty-one".
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