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940299110504197 is a prime number
BaseRepresentation
bin1101010111001100100111001…
…0011101101101011100000101
311120022022201100201221201202221
43111303021302131231130011
51441221330034242113242
613131503240433132341
7402026240345340253
oct32563116235553405
94508281321851687
10940299110504197
11252676682372434
12895643256ba0b1
1331489a96c4b602
141282aa110db5d3
1573a950eca3167
hex357327276d705

940299110504197 has 2 divisors, whose sum is σ = 940299110504198. Its totient is φ = 940299110504196.

The previous prime is 940299110504189. The next prime is 940299110504297. The reversal of 940299110504197 is 791405011992049.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 802841283478116 + 137457827026081 = 28334454^2 + 11724241^2 .

It is a cyclic number.

It is not a de Polignac number, because 940299110504197 - 23 = 940299110504189 is a prime.

It is a super-2 number, since 2×9402991105041972 (a number of 31 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (940299110504297) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 470149555252098 + 470149555252099.

It is an arithmetic number, because the mean of its divisors is an integer number (470149555252099).

Almost surely, 2940299110504197 is an apocalyptic number.

It is an amenable number.

940299110504197 is a deficient number, since it is larger than the sum of its proper divisors (1).

940299110504197 is an equidigital number, since it uses as much as digits as its factorization.

940299110504197 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 7348320, while the sum is 61.

The spelling of 940299110504197 in words is "nine hundred forty trillion, two hundred ninety-nine billion, one hundred ten million, five hundred four thousand, one hundred ninety-seven".