Base | Representation |
---|---|
bin | 10101011000010111000100… |
… | …010110110010100111001011 |
3 | 110022221110122101011101220012 |
4 | 111120113010112302213023 |
5 | 44311114102402221024 |
6 | 531554100413422135 |
7 | 25543442505210605 |
oct | 2530270426624713 |
9 | 408843571141805 |
10 | 94033013320139 |
11 | 27a641a4646883 |
12 | a668289a9a94b |
13 | 406137654760a |
14 | 1931317740175 |
15 | ad1033c8650e |
hex | 5585c45b29cb |
94033013320139 has 2 divisors, whose sum is σ = 94033013320140. Its totient is φ = 94033013320138.
The previous prime is 94033013320069. The next prime is 94033013320241. The reversal of 94033013320139 is 93102331033049.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 94033013320139 - 244 = 76440827275723 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 94033013320096 and 94033013320105.
It is not a weakly prime, because it can be changed into another prime (94033013322139) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 47016506660069 + 47016506660070.
It is an arithmetic number, because the mean of its divisors is an integer number (47016506660070).
Almost surely, 294033013320139 is an apocalyptic number.
94033013320139 is a deficient number, since it is larger than the sum of its proper divisors (1).
94033013320139 is an equidigital number, since it uses as much as digits as its factorization.
94033013320139 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 157464, while the sum is 41.
The spelling of 94033013320139 in words is "ninety-four trillion, thirty-three billion, thirteen million, three hundred twenty thousand, one hundred thirty-nine".
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