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941122623541 is a prime number
BaseRepresentation
bin11011011000111110100…
…01111001100000110101
310022222012110020210201111
431230133101321200311
5110404404342423131
62000202403555021
7124664616211162
oct15543721714065
93288173223644
10941122623541
11333145205591
1213249008ba71
136a9942b0949
143379cb01069
1519732867ab1
hexdb1f479835

941122623541 has 2 divisors, whose sum is σ = 941122623542. Its totient is φ = 941122623540.

The previous prime is 941122623499. The next prime is 941122623547. The reversal of 941122623541 is 145326221149.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 910373598225 + 30749025316 = 954135^2 + 175354^2 .

It is an emirp because it is prime and its reverse (145326221149) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-941122623541 is a prime.

It is a super-3 number, since 3×9411226235413 (a number of 37 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 941122623494 and 941122623503.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (941122623547) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 470561311770 + 470561311771.

It is an arithmetic number, because the mean of its divisors is an integer number (470561311771).

Almost surely, 2941122623541 is an apocalyptic number.

It is an amenable number.

941122623541 is a deficient number, since it is larger than the sum of its proper divisors (1).

941122623541 is an equidigital number, since it uses as much as digits as its factorization.

941122623541 is an evil number, because the sum of its binary digits is even.

The product of its digits is 103680, while the sum is 40.

The spelling of 941122623541 in words is "nine hundred forty-one billion, one hundred twenty-two million, six hundred twenty-three thousand, five hundred forty-one".