Search a number
-
+
943630441997 is a prime number
BaseRepresentation
bin11011011101101001100…
…00011101111000001101
310100012200020011011220112
431232310300131320031
5110430023343120442
62001255311125405
7125114020262225
oct15566460357015
93305606134815
10943630441997
11334211869721
12132a6bb13865
136aca3a199a9
1433959bc9085
151982cada082
hexdbb4c1de0d

943630441997 has 2 divisors, whose sum is σ = 943630441998. Its totient is φ = 943630441996.

The previous prime is 943630441931. The next prime is 943630442021. The reversal of 943630441997 is 799144036349.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 533083975876 + 410546466121 = 730126^2 + 640739^2 .

It is an emirp because it is prime and its reverse (799144036349) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 943630441997 - 214 = 943630425613 is a prime.

It is a super-3 number, since 3×9436304419973 (a number of 37 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (943630441597) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 471815220998 + 471815220999.

It is an arithmetic number, because the mean of its divisors is an integer number (471815220999).

Almost surely, 2943630441997 is an apocalyptic number.

It is an amenable number.

943630441997 is a deficient number, since it is larger than the sum of its proper divisors (1).

943630441997 is an equidigital number, since it uses as much as digits as its factorization.

943630441997 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 17635968, while the sum is 59.

The spelling of 943630441997 in words is "nine hundred forty-three billion, six hundred thirty million, four hundred forty-one thousand, nine hundred ninety-seven".