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944352198017 is a prime number
BaseRepresentation
bin11011011110111111100…
…01101111110110000001
310100021112112021012000222
431233133301233312001
5110433013130314032
62001455052552425
7125140633145204
oct15573761576601
93307475235028
10944352198017
113345522186a8
12133031782715
136b08a405867
14339c79c793b
1519871158a12
hexdbdfc6fd81

944352198017 has 2 divisors, whose sum is σ = 944352198018. Its totient is φ = 944352198016.

The previous prime is 944352197983. The next prime is 944352198019. The reversal of 944352198017 is 710891253449.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 666964589041 + 277387608976 = 816679^2 + 526676^2 .

It is a cyclic number.

It is not a de Polignac number, because 944352198017 - 212 = 944352193921 is a prime.

Together with 944352198019, it forms a pair of twin primes.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 944352198017.

It is not a weakly prime, because it can be changed into another prime (944352198019) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 472176099008 + 472176099009.

It is an arithmetic number, because the mean of its divisors is an integer number (472176099009).

Almost surely, 2944352198017 is an apocalyptic number.

It is an amenable number.

944352198017 is a deficient number, since it is larger than the sum of its proper divisors (1).

944352198017 is an equidigital number, since it uses as much as digits as its factorization.

944352198017 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2177280, while the sum is 53.

The spelling of 944352198017 in words is "nine hundred forty-four billion, three hundred fifty-two million, one hundred ninety-eight thousand, seventeen".