Base | Representation |
---|---|
bin | 101100001100010011… |
… | …0010101101011011001 |
3 | 100001221212211021221212 |
4 | 1120120212111223121 |
5 | 3023324401441321 |
6 | 111333010512505 |
7 | 6566521360661 |
oct | 1303046255331 |
9 | 301855737855 |
10 | 94901983961 |
11 | 3727a772204 |
12 | 16486595735 |
13 | 8c455833c5 |
14 | 4843d671a1 |
15 | 27068c155b |
hex | 1618995ad9 |
94901983961 has 2 divisors, whose sum is σ = 94901983962. Its totient is φ = 94901983960.
The previous prime is 94901983949. The next prime is 94901983973. The reversal of 94901983961 is 16938910949.
It is a balanced prime because it is at equal distance from previous prime (94901983949) and next prime (94901983973).
It can be written as a sum of positive squares in only one way, i.e., 92009695561 + 2892288400 = 303331^2 + 53780^2 .
It is a cyclic number.
It is not a de Polignac number, because 94901983961 - 234 = 77722114777 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 94901983961.
It is not a weakly prime, because it can be changed into another prime (94901983861) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 47450991980 + 47450991981.
It is an arithmetic number, because the mean of its divisors is an integer number (47450991981).
Almost surely, 294901983961 is an apocalyptic number.
It is an amenable number.
94901983961 is a deficient number, since it is larger than the sum of its proper divisors (1).
94901983961 is an equidigital number, since it uses as much as digits as its factorization.
94901983961 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3779136, while the sum is 59.
The spelling of 94901983961 in words is "ninety-four billion, nine hundred one million, nine hundred eighty-three thousand, nine hundred sixty-one".
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