Base | Representation |
---|---|
bin | 11011101000010010101… |
… | …11100011011111000011 |
3 | 10100202102110222212020111 |
4 | 31310021113203133003 |
5 | 111023224301121034 |
6 | 2004042324452151 |
7 | 125405436602155 |
oct | 15641127433703 |
9 | 3322373885214 |
10 | 949344942019 |
11 | 33668451a111 |
12 | 133ba584a057 |
13 | 6b6a48c3856 |
14 | 33d3cb1aad5 |
15 | 19a6462a364 |
hex | dd095e37c3 |
949344942019 has 2 divisors, whose sum is σ = 949344942020. Its totient is φ = 949344942018.
The previous prime is 949344942017. The next prime is 949344942043. The reversal of 949344942019 is 910249443949.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 949344942019 - 21 = 949344942017 is a prime.
It is a super-2 number, since 2×9493449420192 (a number of 25 digits) contains 22 as substring.
Together with 949344942017, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (949344942011) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 474672471009 + 474672471010.
It is an arithmetic number, because the mean of its divisors is an integer number (474672471010).
Almost surely, 2949344942019 is an apocalyptic number.
949344942019 is a deficient number, since it is larger than the sum of its proper divisors (1).
949344942019 is an equidigital number, since it uses as much as digits as its factorization.
949344942019 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 10077696, while the sum is 58.
The spelling of 949344942019 in words is "nine hundred forty-nine billion, three hundred forty-four million, nine hundred forty-two thousand, nineteen".
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