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9494113 is a prime number
BaseRepresentation
bin100100001101…
…111001100001
3122212100110211
4210031321201
54412302423
6535254121
7143461426
oct44157141
918770424
109494113
1153a5082
12321a341
131c75525
141391d4d
15c7810d
hex90de61

9494113 has 2 divisors, whose sum is σ = 9494114. Its totient is φ = 9494112.

The previous prime is 9494081. The next prime is 9494123. The reversal of 9494113 is 3114949.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 5071504 + 4422609 = 2252^2 + 2103^2 .

It is an emirp because it is prime and its reverse (3114949) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 9494113 - 25 = 9494081 is a prime.

It is not a weakly prime, because it can be changed into another prime (9494123) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 4747056 + 4747057.

It is an arithmetic number, because the mean of its divisors is an integer number (4747057).

Almost surely, 29494113 is an apocalyptic number.

It is an amenable number.

9494113 is a deficient number, since it is larger than the sum of its proper divisors (1).

9494113 is an equidigital number, since it uses as much as digits as its factorization.

9494113 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 3888, while the sum is 31.

The square root of 9494113 is about 3081.2518559832. The cubic root of 9494113 is about 211.7474222898.

The spelling of 9494113 in words is "nine million, four hundred ninety-four thousand, one hundred thirteen".