949420133 has 2 divisors, whose sum is σ = 949420134. Its totient is φ = 949420132.

The previous prime is 949420081. The next prime is 949420141. The reversal of 949420133 is 331024949.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 944763169 + 4656964 = 30737^2 + 2158^2 .

It is an emirp because it is prime and its reverse (331024949) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 949420133 - 2¹⁰ = 949419109 is a prime.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 949420093 and 949420102.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (949420033) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 474710066 + 474710067.

It is an arithmetic number, because the mean of its divisors is an integer number (474710067).

Almost surely, 2^949420133 is an apocalyptic number.

It is an amenable number.

949420133 is a deficient number, since it is larger than the sum of its proper divisors (1).

949420133 is an equidigital number, since it uses as much as digits as its factorization.

949420133 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 23328, while the sum is 35.

The square root of 949420133 is about 30812.6618940980. The cubic root of 949420133 is about 982.8475188540.

The spelling of 949420133 in words is "nine hundred forty-nine million, four hundred twenty thousand, one hundred thirty-three".