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94984303 is a prime number
BaseRepresentation
bin1011010100101…
…01100001101111
320121201200222011
411222111201233
5143303444203
613231502051
72232232111
oct552254157
9217650864
1094984303
1149686127
1227987927
13168a883b
14c8873b1
15851376d
hex5a9586f

94984303 has 2 divisors, whose sum is σ = 94984304. Its totient is φ = 94984302.

The previous prime is 94984289. The next prime is 94984313. The reversal of 94984303 is 30348949.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 94984303 - 213 = 94976111 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (94984313) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 47492151 + 47492152.

It is an arithmetic number, because the mean of its divisors is an integer number (47492152).

Almost surely, 294984303 is an apocalyptic number.

94984303 is a deficient number, since it is larger than the sum of its proper divisors (1).

94984303 is an equidigital number, since it uses as much as digits as its factorization.

94984303 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 93312, while the sum is 40.

The square root of 94984303 is about 9745.9890724338. The cubic root of 94984303 is about 456.2651309675.

The spelling of 94984303 in words is "ninety-four million, nine hundred eighty-four thousand, three hundred three".