Base | Representation |
---|---|
bin | 101100010000100001… |
… | …1001101101011101001 |
3 | 100002022202121211100212 |
4 | 1120201003031223221 |
5 | 3024122201133423 |
6 | 111355033510505 |
7 | 6603162503414 |
oct | 1304103155351 |
9 | 302282554325 |
10 | 95043771113 |
11 | 37342804a75 |
12 | 16505b72435 |
13 | 8c68a68025 |
14 | 4858b14b7b |
15 | 271407c578 |
hex | 16210cdae9 |
95043771113 has 4 divisors (see below), whose sum is σ = 95047601040. Its totient is φ = 95039941188.
The previous prime is 95043771083. The next prime is 95043771167. The reversal of 95043771113 is 31117734059.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-95043771113 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (95043771313) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1877495 + ... + 1927452.
It is an arithmetic number, because the mean of its divisors is an integer number (23761900260).
Almost surely, 295043771113 is an apocalyptic number.
It is an amenable number.
95043771113 is a deficient number, since it is larger than the sum of its proper divisors (3829927).
95043771113 is a wasteful number, since it uses less digits than its factorization.
95043771113 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 3829926.
The product of its (nonzero) digits is 79380, while the sum is 41.
The spelling of 95043771113 in words is "ninety-five billion, forty-three million, seven hundred seventy-one thousand, one hundred thirteen".
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