Base | Representation |
---|---|
bin | 101100010011001010… |
… | …1110110010010010111 |
3 | 100002112221122212021022 |
4 | 1120212111312102113 |
5 | 3024312412321403 |
6 | 111411524311355 |
7 | 6605321160104 |
oct | 1304625662227 |
9 | 302487585238 |
10 | 95132542103 |
11 | 37388926a25 |
12 | 1652b84255b |
13 | 8c81279741 |
14 | 4866821aab |
15 | 271bc64d38 |
hex | 1626576497 |
95132542103 has 2 divisors, whose sum is σ = 95132542104. Its totient is φ = 95132542102.
The previous prime is 95132542097. The next prime is 95132542121. The reversal of 95132542103 is 30124523159.
It is a weak prime.
It is an emirp because it is prime and its reverse (30124523159) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 95132542103 - 228 = 94864106647 is a prime.
It is a super-4 number, since 4×951325421034 (a number of 45 digits) contains 4444 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (95132548103) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 47566271051 + 47566271052.
It is an arithmetic number, because the mean of its divisors is an integer number (47566271052).
Almost surely, 295132542103 is an apocalyptic number.
95132542103 is a deficient number, since it is larger than the sum of its proper divisors (1).
95132542103 is an equidigital number, since it uses as much as digits as its factorization.
95132542103 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 32400, while the sum is 35.
The spelling of 95132542103 in words is "ninety-five billion, one hundred thirty-two million, five hundred forty-two thousand, one hundred three".
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