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95189628073 is a prime number
BaseRepresentation
bin101100010100110111…
…1100111010010101001
3100002200221002010111111
41120221233213102221
53024422021044243
6111421324030321
76606613326361
oct1305157472251
9302627063444
1095189628073
1137408077511
12165469923a1
138c90046217
1448702419a1
152721c8e39d
hex1629be74a9

95189628073 has 2 divisors, whose sum is σ = 95189628074. Its totient is φ = 95189628072.

The previous prime is 95189628071. The next prime is 95189628097. The reversal of 95189628073 is 37082698159.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 63914412969 + 31275215104 = 252813^2 + 176848^2 .

It is a cyclic number.

It is not a de Polignac number, because 95189628073 - 21 = 95189628071 is a prime.

It is a super-2 number, since 2×951896280732 (a number of 23 digits) contains 22 as substring.

Together with 95189628071, it forms a pair of twin primes.

It is a junction number, because it is equal to n+sod(n) for n = 95189627999 and 95189628017.

It is not a weakly prime, because it can be changed into another prime (95189628071) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 47594814036 + 47594814037.

It is an arithmetic number, because the mean of its divisors is an integer number (47594814037).

Almost surely, 295189628073 is an apocalyptic number.

It is an amenable number.

95189628073 is a deficient number, since it is larger than the sum of its proper divisors (1).

95189628073 is an equidigital number, since it uses as much as digits as its factorization.

95189628073 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 6531840, while the sum is 58.

The spelling of 95189628073 in words is "ninety-five billion, one hundred eighty-nine million, six hundred twenty-eight thousand, seventy-three".