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95255250037 = 929102535253
BaseRepresentation
bin101100010110110100…
…1111100010001110101
3100002212111120001220121
41120231221330101311
53030040321000122
6111432030331541
76611341160143
oct1305551742165
9302774501817
1095255250037
1137441118242
1216564959bb1
138ca081109c
144878c44593
152727902bc7
hex162da7c475

95255250037 has 4 divisors (see below), whose sum is σ = 95357786220. Its totient is φ = 95152713856.

The previous prime is 95255250023. The next prime is 95255250071. The reversal of 95255250037 is 73005255259.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 32719744996 + 62535505041 = 180886^2 + 250071^2 .

It is a cyclic number.

It is not a de Polignac number, because 95255250037 - 227 = 95121032309 is a prime.

It is a super-2 number, since 2×952552500372 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 95255249975 and 95255250002.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (95255850037) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 51266698 + ... + 51268555.

It is an arithmetic number, because the mean of its divisors is an integer number (23839446555).

Almost surely, 295255250037 is an apocalyptic number.

It is an amenable number.

95255250037 is a deficient number, since it is larger than the sum of its proper divisors (102536183).

95255250037 is a wasteful number, since it uses less digits than its factorization.

95255250037 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 102536182.

The product of its (nonzero) digits is 472500, while the sum is 43.

The spelling of 95255250037 in words is "ninety-five billion, two hundred fifty-five million, two hundred fifty thousand, thirty-seven".

Divisors: 1 929 102535253 95255250037