953000149 has 2 divisors, whose sum is σ = 953000150. Its totient is φ = 953000148.

The previous prime is 953000143. The next prime is 953000179. The reversal of 953000149 is 941000359.

953000149 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 552720100 + 400280049 = 23510^2 + 20007^2 .

It is a cyclic number.

It is not a de Polignac number, because 953000149 - 2³ = 953000141 is a prime.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 953000149.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (953000141) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 476500074 + 476500075.

It is an arithmetic number, because the mean of its divisors is an integer number (476500075).

Almost surely, 2^953000149 is an apocalyptic number.

It is an amenable number.

953000149 is a deficient number, since it is larger than the sum of its proper divisors (1).

953000149 is an equidigital number, since it uses as much as digits as its factorization.

953000149 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 4860, while the sum is 31.

The square root of 953000149 is about 30870.7004941579. The cubic root of 953000149 is about 984.0813233540.

The spelling of 953000149 in words is "nine hundred fifty-three million, one hundred forty-nine", and thus it is an aban number.