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954011212213 is a prime number
BaseRepresentation
bin11011110000111110111…
…11111101100110110101
310101012110200101221120111
431320133133331212311
5111112303332242323
62010133335103021
7125632200335353
oct15703737754665
93335420357514
10954011212213
11338659504a64
12134a88511a71
136bc69574a87
14342627487d3
1519c3910dc0d
hexde1f7fd9b5

954011212213 has 2 divisors, whose sum is σ = 954011212214. Its totient is φ = 954011212212.

The previous prime is 954011212201. The next prime is 954011212261. The reversal of 954011212213 is 312212110459.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 858407809009 + 95603403204 = 926503^2 + 309198^2 .

It is a cyclic number.

It is not a de Polignac number, because 954011212213 - 29 = 954011211701 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (954011242213) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 477005606106 + 477005606107.

It is an arithmetic number, because the mean of its divisors is an integer number (477005606107).

Almost surely, 2954011212213 is an apocalyptic number.

It is an amenable number.

954011212213 is a deficient number, since it is larger than the sum of its proper divisors (1).

954011212213 is an equidigital number, since it uses as much as digits as its factorization.

954011212213 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 4320, while the sum is 31.

The spelling of 954011212213 in words is "nine hundred fifty-four billion, eleven million, two hundred twelve thousand, two hundred thirteen".