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9540774213253 is a prime number
BaseRepresentation
bin1000101011010110001001…
…1101010011011010000101
31020210002101221220012000021
42022311202131103122011
52222304001144311003
632142545434415141
72003204164512133
oct212654235233205
936702357805007
109540774213253
113049246352528
1210a1095b914b1
135428ca5b486a
1424dac124c753
1511829dc782bd
hex8ad62753685

9540774213253 has 2 divisors, whose sum is σ = 9540774213254. Its totient is φ = 9540774213252.

The previous prime is 9540774213211. The next prime is 9540774213283. The reversal of 9540774213253 is 3523124770459.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 8302045280929 + 1238728932324 = 2881327^2 + 1112982^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-9540774213253 is a prime.

It is a super-2 number, since 2×95407742132532 (a number of 27 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 9540774213253.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (9540774213283) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 4770387106626 + 4770387106627.

It is an arithmetic number, because the mean of its divisors is an integer number (4770387106627).

Almost surely, 29540774213253 is an apocalyptic number.

It is an amenable number.

9540774213253 is a deficient number, since it is larger than the sum of its proper divisors (1).

9540774213253 is an equidigital number, since it uses as much as digits as its factorization.

9540774213253 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 6350400, while the sum is 52.

The spelling of 9540774213253 in words is "nine trillion, five hundred forty billion, seven hundred seventy-four million, two hundred thirteen thousand, two hundred fifty-three".