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954473000989 is a prime number
BaseRepresentation
bin11011110001110110000…
…01100011000000011101
310101020122212100020200111
431320323001203000131
5111114230042012424
62010251232530021
7125646505434334
oct15707301430035
93336585306614
10954473000989
11338876142782
12134b970b0911
136c01113b581
14342a7bd4d1b
1519c6492a194
hexde3b06301d

954473000989 has 2 divisors, whose sum is σ = 954473000990. Its totient is φ = 954473000988.

The previous prime is 954473000939. The next prime is 954473001019. The reversal of 954473000989 is 989000374459.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 932850768964 + 21622232025 = 965842^2 + 147045^2 .

It is an emirp because it is prime and its reverse (989000374459) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 954473000989 - 215 = 954472968221 is a prime.

It is a super-2 number, since 2×9544730009892 (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (954473000939) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 477236500494 + 477236500495.

It is an arithmetic number, because the mean of its divisors is an integer number (477236500495).

Almost surely, 2954473000989 is an apocalyptic number.

It is an amenable number.

954473000989 is a deficient number, since it is larger than the sum of its proper divisors (1).

954473000989 is an equidigital number, since it uses as much as digits as its factorization.

954473000989 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 9797760, while the sum is 58.

The spelling of 954473000989 in words is "nine hundred fifty-four billion, four hundred seventy-three million, nine hundred eighty-nine", and thus it is an aban number.