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95472264413 is a prime number
BaseRepresentation
bin101100011101010010…
…1110010010011011101
3100010102121220112200002
41120322211302103131
53031011344430123
6111505341544045
76616614600131
oct1307245622335
9303377815602
1095472264413
1137542671369
1216605575025
139006774866
1448999b53c1
15273b9bd528
hex163a9724dd

95472264413 has 2 divisors, whose sum is σ = 95472264414. Its totient is φ = 95472264412.

The previous prime is 95472264383. The next prime is 95472264431. The reversal of 95472264413 is 31446227459.

Together with next prime (95472264431) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 94290142489 + 1182121924 = 307067^2 + 34382^2 .

It is a cyclic number.

It is not a de Polignac number, because 95472264413 - 232 = 91177297117 is a prime.

It is a super-2 number, since 2×954722644132 (a number of 23 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (95472264313) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 47736132206 + 47736132207.

It is an arithmetic number, because the mean of its divisors is an integer number (47736132207).

Almost surely, 295472264413 is an apocalyptic number.

It is an amenable number.

95472264413 is a deficient number, since it is larger than the sum of its proper divisors (1).

95472264413 is an equidigital number, since it uses as much as digits as its factorization.

95472264413 is an evil number, because the sum of its binary digits is even.

The product of its digits is 1451520, while the sum is 47.

The spelling of 95472264413 in words is "ninety-five billion, four hundred seventy-two million, two hundred sixty-four thousand, four hundred thirteen".