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95535342403 is a prime number
BaseRepresentation
bin101100011111001011…
…0011010001101000011
3100010121000121020101221
41120332112122031003
53031124021424103
6111515513535511
76621312004024
oct1307626321503
9303530536357
1095535342403
1137575234836
1216622714597
13901685b807
1448a4114c4b
1527422cd1bd
hex163e59a343

95535342403 has 2 divisors, whose sum is σ = 95535342404. Its totient is φ = 95535342402.

The previous prime is 95535342317. The next prime is 95535342421. The reversal of 95535342403 is 30424353559.

It is a happy number.

It is a strong prime.

It is an emirp because it is prime and its reverse (30424353559) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-95535342403 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 95535342403.

It is not a weakly prime, because it can be changed into another prime (95565342403) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 47767671201 + 47767671202.

It is an arithmetic number, because the mean of its divisors is an integer number (47767671202).

Almost surely, 295535342403 is an apocalyptic number.

95535342403 is a deficient number, since it is larger than the sum of its proper divisors (1).

95535342403 is an equidigital number, since it uses as much as digits as its factorization.

95535342403 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 972000, while the sum is 43.

The spelling of 95535342403 in words is "ninety-five billion, five hundred thirty-five million, three hundred forty-two thousand, four hundred three".