959314028243 has 2 divisors, whose sum is σ = 959314028244. Its totient is φ = 959314028242.

The previous prime is 959314028227. The next prime is 959314028333. The reversal of 959314028243 is 342820413959.

It is a happy number.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 959314028243 - 2⁴ = 959314028227 is a prime.

It is a super-2 number, since 2×959314028243² (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 959314028191 and 959314028200.

It is not a weakly prime, because it can be changed into another prime (959313028243) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 479657014121 + 479657014122.

It is an arithmetic number, because the mean of its divisors is an integer number (479657014122).

Almost surely, 2^959314028243 is an apocalyptic number.

959314028243 is a deficient number, since it is larger than the sum of its proper divisors (1).

959314028243 is an equidigital number, since it uses as much as digits as its factorization.

959314028243 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1866240, while the sum is 50.

The spelling of 959314028243 in words is "nine hundred fifty-nine billion, three hundred fourteen million, twenty-eight thousand, two hundred forty-three".