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959988000073 is a prime number
BaseRepresentation
bin11011111100000111011…
…11100110010101001001
310101202220012210020011211
431332003233212111021
5111212023412000243
62013002402253121
7126233253236014
oct15760357462511
93352805706154
10959988000073
11340146221163
121360760571a1
136c6ac8a433b
143466c43437b
1519e88badd9d
hexdf83be6549

959988000073 has 2 divisors, whose sum is σ = 959988000074. Its totient is φ = 959988000072.

The previous prime is 959988000019. The next prime is 959988000091. The reversal of 959988000073 is 370000889959.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 912200728464 + 47787271609 = 955092^2 + 218603^2 .

It is a cyclic number.

It is not a de Polignac number, because 959988000073 - 29 = 959987999561 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 959987999981 and 959988000017.

It is not a weakly prime, because it can be changed into another prime (959986000073) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 479994000036 + 479994000037.

It is an arithmetic number, because the mean of its divisors is an integer number (479994000037).

Almost surely, 2959988000073 is an apocalyptic number.

It is an amenable number.

959988000073 is a deficient number, since it is larger than the sum of its proper divisors (1).

959988000073 is an equidigital number, since it uses as much as digits as its factorization.

959988000073 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 4898880, while the sum is 58.

The spelling of 959988000073 in words is "nine hundred fifty-nine billion, nine hundred eighty-eight million, seventy-three", and thus it is an aban number.