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96125550043387 is a prime number
BaseRepresentation
bin10101110110110011111001…
…010000111010000011111011
3110121100111211212011212002111
4111312303321100322003323
5100044410111302342022
6540235245033513151
726150561511661054
oct2566637120720373
9417314755155074
1096125550043387
11286a0687014447
12a9459382727b7
1341837a631a617
1419a4703d7b72b
15b1a6a5b72477
hex576cf943a0fb

96125550043387 has 2 divisors, whose sum is σ = 96125550043388. Its totient is φ = 96125550043386.

The previous prime is 96125550043339. The next prime is 96125550043463. The reversal of 96125550043387 is 78334005552169.

It is a weak prime.

It is an emirp because it is prime and its reverse (78334005552169) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-96125550043387 is a prime.

It is a super-2 number, since 2×961255500433872 (a number of 29 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (96125550043687) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 48062775021693 + 48062775021694.

It is an arithmetic number, because the mean of its divisors is an integer number (48062775021694).

It is a 1-persistent number, because it is pandigital, but 2⋅96125550043387 = 192251100086774 is not.

Almost surely, 296125550043387 is an apocalyptic number.

96125550043387 is a deficient number, since it is larger than the sum of its proper divisors (1).

96125550043387 is an equidigital number, since it uses as much as digits as its factorization.

96125550043387 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 27216000, while the sum is 58.

The spelling of 96125550043387 in words is "ninety-six trillion, one hundred twenty-five billion, five hundred fifty million, forty-three thousand, three hundred eighty-seven".