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96125550043463 is a prime number
BaseRepresentation
bin10101110110110011111001…
…010000111010000101000111
3110121100111211212011212012022
4111312303321100322011013
5100044410111302342323
6540235245033513355
726150561511661223
oct2566637120720507
9417314755155168
1096125550043463
11286a0687014506
12a94593827285b
1341837a631a675
1419a4703d7b783
15b1a6a5b724c8
hex576cf943a147

96125550043463 has 2 divisors, whose sum is σ = 96125550043464. Its totient is φ = 96125550043462.

The previous prime is 96125550043387. The next prime is 96125550043489. The reversal of 96125550043463 is 36434005552169.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 96125550043463 - 212 = 96125550039367 is a prime.

It is a super-2 number, since 2×961255500434632 (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (96125550043063) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 48062775021731 + 48062775021732.

It is an arithmetic number, because the mean of its divisors is an integer number (48062775021732).

Almost surely, 296125550043463 is an apocalyptic number.

96125550043463 is a deficient number, since it is larger than the sum of its proper divisors (1).

96125550043463 is an equidigital number, since it uses as much as digits as its factorization.

96125550043463 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 11664000, while the sum is 53.

The spelling of 96125550043463 in words is "ninety-six trillion, one hundred twenty-five billion, five hundred fifty million, forty-three thousand, four hundred sixty-three".