Base | Representation |
---|---|
bin | 11011111111110110101… |
… | …01011100101110010111 |
3 | 10101222002001012110102001 |
4 | 31333323111130232113 |
5 | 111230131032122103 |
6 | 2013533434500131 |
7 | 126334055401201 |
oct | 15777325345627 |
9 | 3358061173361 |
10 | 961994410903 |
11 | 340a85847329 |
12 | 136535b94647 |
13 | 6c93c484696 |
14 | 347bcabb771 |
15 | 1a054ddb01d |
hex | dffb55cb97 |
961994410903 has 2 divisors, whose sum is σ = 961994410904. Its totient is φ = 961994410902.
The previous prime is 961994410879. The next prime is 961994410933. The reversal of 961994410903 is 309014499169.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-961994410903 is a prime.
It is a super-2 number, since 2×9619944109032 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (961994410933) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 480997205451 + 480997205452.
It is an arithmetic number, because the mean of its divisors is an integer number (480997205452).
Almost surely, 2961994410903 is an apocalyptic number.
961994410903 is a deficient number, since it is larger than the sum of its proper divisors (1).
961994410903 is an equidigital number, since it uses as much as digits as its factorization.
961994410903 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1889568, while the sum is 55.
The spelling of 961994410903 in words is "nine hundred sixty-one billion, nine hundred ninety-four million, four hundred ten thousand, nine hundred three".
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